|
Contents | Previous | Next | Subchapters |
| Syntax |
interp2(xz, yz, z, xi, yi) |
| See Also | interp2 , interp , smospl |
z(i,j) at the point (yz(i, 1), xz(1, j))
for i = 1 to the row dimension of yz and
j = 1 to the column dimension of xz.
The (i,j)-th element of the return value is the value of the
interpolant at (yi(i, 1), xi(1, j))
for i = 1 to the row dimension of yi and
j = 1 to the column dimension of xi.
The return value has the same type as z,
the same row dimension as yi,
and the same column dimension as xi.
Both the row and column dimensions of z must be greater than 1.
The matrix yz has the same number of rows as z.
The matrix xz has the same number of columns as z.
The vectors
yz(:,1),
xz(1,:),
yi(:,1),
xi(:,1)
are integer, real, or double-precision.
In addition, the vectors
yz(:,1),
xz(1,:),
are strictly monotone
increasing or decreasing.
If z is complex,
the return value is complex.
If all the arguments are real,
the return value is real.
Otherwise the return value is double-precision.
interp2 to interpolate the
function x y between 1 and 5 in both the x
and y directions.
The interpolation exactly matches the function because
x y is bilinear.
If in Mlmode
you enter
xz = [1. , 5.];
yz = xz';
z = yz * xz;
xi = [1. , 2. , 3. , 4. , 5.];
yi = xi';
interp2(xz, yz, z, xi, yi)
O-Matrix will respond
{
[ 1 , 2 , 3 , 4 , 5 ]
[ 2 , 4 , 6 , 8 , 10 ]
[ 3 , 6 , 9 , 12 , 15 ]
[ 4 , 8 , 12 , 16 , 20 ]
[ 5 , 10 , 15 , 20 , 25 ]
}
f(x,y) is bilinear if its second partial derivative
with respect to x and its second partial derivative with
respect to y is zero.
The interpolating function is continuous and it is
bilinear over rectangles of the form
{(x,y) : xz < x < xz and yz < y < yz }
i i+1 i i+1