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| Syntax |
interp2(z, xz, yz, xi, yi) |
| See Also | mlmode_interp2 , interp , smospl |
z(i,j) at the point (xz(i), yz(j))
for i = 1 to the row dimension of xz and
j = 1 to the column dimension of yz.
The (i,j)-th element of the return value is the value of the
interpolant at (xi(i), yi(j))
for i = 1 to the row dimension of xi and
j = 1 to the column dimension of yi.
The return value has the same type as z,
the same row dimension as xi,
and the same column dimension as yi.
Both the row and column dimensions of z must be greater than 1.
The column vector xz has the same number of rows as z.
The row vector yz has the same number of columns as z.
interp2 to interpolate the
function x y between 1 and 5 in both the x
and y directions.
The interpolation exactly matches the function because
x y is bilinear.
xz = {1., 5.}
yz = [1., 5.]
z = xz * yz
xi = {1., 2., 3., 4., 5.}
yi = xi'
interp2(z, xz, yz, xi, yi)
returns
{
[ 1 , 2 , 3 , 4 , 5 ]
[ 2 , 4 , 6 , 8 , 10 ]
[ 3 , 6 , 9 , 12 , 15 ]
[ 4 , 8 , 12 , 16 , 20 ]
[ 5 , 10 , 15 , 20 , 25 ]
}
f(x,y) is bilinear if its second partial derivative
with respect to x and its second partial derivative with
respect to y is zero.
The interpolating function is continuous and it is
bilinear over rectangles of the form
{(x,y) : xz < x < xz and yz < y < yz }
i i+1 i i+1