|
Contents | Previous | Next | Subchapters |
| Syntax |
cubespl(x, d, b1, bn) |
| See Also | cubeval , interp , lagrange |
(x(i), d(i)).
Let a, b, and c,
be the first, second, and third columns of the return value.
If z is between x(i) and x(i + 1),
the cubic spline's value at z is equal to
3 2
a (z - x ) + b (z - x ) + c (z - x ) + d
i i i i i i i
The column vector x
must be either real or double-precision and
x(i) < x(i+1) for all i.
The vector d must have the same type and dimension as x.
The scalars b1 and bn
must have the same type as x.
The second derivative of the spline at x(1) 2 b1
and at x(n) is 2 bn,
where n is the row dimension of x.
The return value has the same type as x.
3 3 2
z = 1 (z - 1) + 3 (z - 1) + 3 (z - 1) + d
1
3 2
= 1 (z - 2) + 6 (z - 2) + 12 (z - 2) + d
2
Note that the second derivative of this function is 6 z.
It follows from the equalities above that, the values of
a, b, and c, are 1, 3, 3 in the
first interval and 1, 6, 12 in the second interval.
clear
#
x = {1., 2., 3.}
d = x^3
b1 = 6 * x(1) / 2
bn = 6 * x(3) / 2
cubespl(x, d, b1, bn)