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| Syntax |
atod(text) |
| See Also | char2dbl , atoi , ntoa , double |
x = {"3.50", "4.50"}
2. * atod(x)
results in
{
7
9
}
The atod function ignores
white space
at the beginning of each row.
The number is represented by a sequence of characters from the set
"0" through "9", "D", "d", "E", "e", "+", and "-".
Any other character signals that the number
terminated at the previous character.
If there are no valid characters following leading white space,
zero is returned.
atod({" two", " 4", "+4d3", "-4e3", "4i3"})
results in
{
0
4
4000
-4000
4
}
(Note that the character "i" is not in the set of characters defined above.)